数组去重

<script>
a=[{"z":1},{"z":2},{"z":1}];
var quchong = [{"z":a[0].z}];
console.log(quchong);
alert(a.length);
for(var arr_1=1;arr_1<a.length-1;arr_1++){
var ss=true;
var aa=true;
for(var arr_2=0;arr_2<quchong.length;arr_2++){
if(a[arr_1].z!=quchong[arr_2].z && aa==true){
ss=false;
}
else{
ss=true;
aa=false;
}
}
if(ss==false){
var pro_sum={"z":a[arr_1].z};
quchong.push(pro_sum);
alert(quchong);
console.log(quchong);
}
}

</script>
原文地址:https://www.cnblogs.com/boonook/p/7814706.html