LeetCode 344. Reverse String

344. Reverse String(反转字符串)

链接

https://leetcode-cn.com/problems/reverse-string

题目

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

示例 1:

输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:

输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]

思路

就硬转呗,双指针,一头一尾直接转换位置,当指针相遇就结束。

代码

public void reverseString(char[] s) {
    int left = 0, right = s.length - 1;
    while (left < right) {
      char temp = s[left];
      s[left] = s[right];
      s[right] = temp;
      left++;
      right--;
    }
  }
原文地址:https://www.cnblogs.com/blogxjc/p/12316488.html