leetcode1 两数之和

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        unordered_map<int,int> um;
        vector<int> res;

        for(int i=0;i<nums.size();i++){
            int tem=target-nums[i];
            if(um.count(tem)){
                res.push_back(um[tem]);
                res.push_back(i);
                
                return res;
            }
            um[nums[i]]=i;
        }
    }
};

边判断边记录,不需要考虑重复。O(n)

原文地址:https://www.cnblogs.com/azureice/p/leetcode1.html