oracle 产生节假日表

说明:

将指定年份一整年365天对应的是否为工作日情况数据插入到指定表中 work_days(TYPE:0表示工作日,1表示双休日,法定节假日手动调整)

1.创建表:

create table WORK_DAYS
(
work_days_id NUMBER not null,
one_day DATE,
type NUMBER,
created_on DATE,
created_by NUMBER,
updated_on DATE,
updated_by NUMBER
)
tablespace WEBSITE
pctfree 10
initrans 1
maxtrans 255
storage
(
initial 64K
next 1M
minextents 1
maxextents unlimited
);

2.oracle表主键自增序列:

create sequence seq_work_days
increment by 1
start with 1
nomaxvalue
nocycle
nocache;

3.查出结果并插入至指定表:

insert into work_days(work_days_id,one_day,type)
with x0 as (select to_date('2018-01-01','yyyy-MM-dd') as 年初,to_date('2018-12-31','yyyy-MM-dd') as 年末 from dual ),
x1 as (select 年初 + level - 1 as 日期 from x0 connect by level <= (年末 - 年初) + 1),
x2 as (select 日期,to_number(to_char(日期, 'd')) 周几 from x1)
select seq_work_days.nextval,日期,(case when 周几=1 or 周几=7 then then 1 else 0 end) as 工作日标志 from x2

 WORK_DAYS 指定年份数据已经生成

下面是根据具体的业务需求扩展解析到具体的数据可自参考:

  

begin
    for rec in (select * from work_days) loop
    insert into t_sys_holiday
       (id, year, month, day, type, modperson, modtime)
       values
 (to_char(sysdate, 'yyyymmddhh24miss') || rec.work_days_id,
 substr(to_char(rec.one_day, 'yyyymmddhh24miss'), 0, 4),
 substr(to_char(rec.one_day, 'yyyymmddhh24miss'), 5, 2),
 substr(to_char(rec.one_day, 'yyyymmddhh24miss'), 7, 2),
 rec.type,
 'zh',
 sysdate);
     end loop;
end;

原文地址:https://www.cnblogs.com/auldlangsynezh/p/8478029.html