50. Pow(x, n)

 public class Solution {
    public double myPow(double x, int n) {
        if(n==0)
            return 1;
        if(n < 0)
            return 1/(x*myPow(x, -(n+1)));
        double t = myPow(x,n/2);
        return n%2 == 1?x*t*t:t*t;
    }
}
原文地址:https://www.cnblogs.com/asuran/p/7590383.html