剑指Offer 55 二叉树的深度

二叉树的深度

输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。

 1 # -*- coding:utf-8 -*-
 2 # class TreeNode:
 3 #     def __init__(self, x):
 4 #         self.val = x
 5 #         self.left = None
 6 #         self.right = None
 7 class Solution:
 8     def __init__(self):
 9         self.maxlen = 0
10     
11     def preOrder(self,root,length):
12         if root != None:
13             length += 1
14             self.preOrder(root.left,length)
15             self.preOrder(root.right,length)
16             if root.left == None and root.right == None:
17                 self.maxlen = max(self.maxlen,length)
18             length -= 1
19         
20     def TreeDepth(self, pRoot):
21         if pRoot == None:
22             return 0
23         self.preOrder(pRoot,0)
24         return self.maxlen
25         # write code here

平衡二叉树

输入一棵二叉树,判断该二叉树是否是平衡二叉树。

 1 # -*- coding:utf-8 -*-
 2 # class TreeNode:
 3 #     def __init__(self, x):
 4 #         self.val = x
 5 #         self.left = None
 6 #         self.right = None
 7 class Solution:
 8     def __init__(self):
 9         self.isBalanced = True
10         
11     def height(self,root):
12         if root == None or not self.isBalanced:
13             return 0
14         left = self.height(root.left)
15         right = self.height(root.right)
16         if abs(left - right) > 1:
17             self.isBalanced = False
18         return 1 + max(left,right)
19         
20     def IsBalanced_Solution(self, pRoot):
21         self.height(pRoot)
22         return self.isBalanced
23         # write code here
原文地址:https://www.cnblogs.com/asenyang/p/11023795.html