提取URL字符串的搜索字符串中的参数

	function urlArgs() {
		var args = [];
		var query = location.search.substring(1);
		var paris = query.split("&");
		for (var i = 0, len = paris.length; i <= len; i++) {
			var pos = paris[i].indexOf('=');
			if (pos == -1) {
				continue;
			}
			var name = paris[i].substring(0, pos);
			var value = paris[i].substring(0pos + 1);
			value = decodeURIComponent(value);
			args[name] = value;
		}
		return args;
	}

  

原文地址:https://www.cnblogs.com/alphafly/p/4782514.html