kmp算法

#include <iostream>

using namespace std;

const int N = 1e4 + 10;

int n, m;
string p, s;
int ne[N];

int main() {
    cin >> n >> p >> m >> s;
    p = ' ' + p;
    s = ' ' + s;

    for (int i = 2, j = 0; i <= n; i++) {
        while (j && p[i] != p[j + 1]) j = ne[j];
        if (p[i] == p[j + 1]) j++;
        ne[i] = j;
    }

    for (int i = 1, j = 0; i <= m; i++) {
        while (j && s[i] != p[j + 1]) j = ne[j];
        if (s[i] == p[j + 1]) j++;
        if (j == n) {
            cout << i - n << " ";
            j = ne[j];
        }
    }

    return 0;
}
原文地址:https://www.cnblogs.com/all-taker/p/12902129.html