用C#写 四舍五入函数(函数版)

适用范围:长整型long(-9223272036854775808 ~  +9223272036854775808)
        //BY: bit.Aipeli 2005-11-07 23:27:23

        
private double Round(double v,int x)
        
{
            
int i;
            long
 IValue=1;
            
double DValue=1;
        
            
for (i=1;i<=x;i++)
            
{
                IValue
=IValue*10;
                DValue
=DValue/10;
            }

            
long Int=(long)Decimal.Round(Convert.ToDecimal(v*IValue),0);
            
double Key=(double)(v/DValue)-Int;
            
double Dou=(double)Int/IValue;

            
if (Key>=0.5)
            
{
                Dou
+=DValue;
            }

            
return Dou;
        }

本代码在:Windows 2003 && Microsoft Visual Studio .NET 2003 通过
原文地址:https://www.cnblogs.com/aipeli/p/271057.html