2014

求出去最高分和最低分的最终得分

 1 #include <stdio.h>
 2 
 3 int main()
 4 {
 5     int i,n;
 6     double grade,defen,max,min;
 7     while (scanf_s("%d", &n))
 8     {
 9         max = 0;
10         min = 100;
11         defen = 0;
12         for (i = 0; i < n; i++)
13         {
14             scanf_s("%lf", &grade);
15             defen += grade;
16 
17             if (max < grade)
18                 max = grade;
19             if (min > grade)
20                 min = grade;
21         }
22         defen = (defen - min - max) / (n - 2);
23         printf("%.2lf", defen);
24     }
25     return 0;
26 }

参考答案

 1 #include <stdio.h>
 2 
 3 int main(void)
 4 {
 5     int n, i;
 6     double min, max;
 7     double x, y;
 8     
 9     while (scanf("%d", &n) != EOF)
10     {
11         scanf("%lf", &x);
12         min = max = x;
13         for (i = 1 ; i < n ; i++)
14         {
15             scanf("%lf", &y);
16             x += y;
17             if (y > max) max = y;
18             if (y < min) min = y;
19         }
20         printf("%.2lf
", (x - min - max) / (n - 2));
21     }
22 
23     return 0;
24 }
========================if i have some wrong, please give me a message, thx.========================
原文地址:https://www.cnblogs.com/ailx10/p/5328175.html