Given a prime p (p<108),you are to find min{x2+y2},where x and y belongs to positive integer, so that x2+y2=0 (mod p).打表可以看出结论: x=4k+3则没有平方和会等于P
Given a prime p (p<108),you are to find min{x2+y2},where x and y belongs to positive integer, so that x2+y2=0 (mod p).打表可以看出结论: x=4k+3则没有平方和会等于P