Problem 9: Special Pythagorean triplet

flag = 0
for a in range(1,1000):
    for b in range(a+1,1000):
        if a*a + b*b == (1000-a-b)**2:
            print(a,b)
            flag = 1
            break
    if flag == 1:
        break

print(a*b*(1000-a-b))
原文地址:https://www.cnblogs.com/Quxiaolong2020/p/8961439.html