【10_169】Majority Element

今天遇到的题都挺难的，不容易有会做的。

下面是代码，等明天看看Discuss里面有没有简单的方法~

Majority Element

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Question

Total Accepted: 79833 Total Submissions: 208075 Difficulty: Easy

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

 Java写法，遇到一个数字就标记一次，最后看谁的标记数目大于 ⌊ n/2 ⌋ 

public class Solution {
    public int majorityElement(int[] nums) {
        int n = nums.length;
        int[][] count = new int[n][2];
        for (int i = 0; i < n; i++) {
            count[i][1] = 0;
        }
        
        count[0][0] = nums[0];
        count[0][1] = 1;
        int ss = 1;
        for (int i = 1; i < n; i++) {
            for (int j = 0; j < ss; j++) {
                if(count[j][0] == nums[i]) {
                    count[j][1]++;
                }
                else if (j == ss - 1)  {
                    count[ss][0] = nums[i];
                    ss++;
                }
            }
        }
        int pan;
        if(n % 2 == 0)  
            pan = n / 2;
        else
            pan = (n - 1) / 2;
        for (int i = 0; i < n; i++) {
            if(count[i][1] > pan)
                return count[i][0];
        }
        
        return 0;
    }
}