1039 到底买不买 (20分)

#include <string.h>
#include <iostream>
using namespace std;

int main()
{
    char sell[1005],want[1005];
    int s[1005]={0};
    int j,n=0;
    cin>>sell>>want;
    for(int i=0;i<strlen(want);i++)
    {
        for(j=0;j<strlen(sell);j++)
        {
            if(want[i]==sell[j]&&s[j]==0)
            {
                s[j]=1;
                break;
            }
        }
        if(j==strlen(sell))
            n++;
    }
    if(n>0)
        cout<<"No "<<n<<endl;
    else
        cout<<"Yes "<<strlen(sell)-strlen(want)<<endl;
    return 0;
}