【luogu P4114 Qtree1】 题解

题目链接:https://www.luogu.org/problemnew/show/P4114
1.把边权转化到点权:选取连接这条边的两个点中较深的一个。
2.查询点到点之间的边权时,要从seg[x]+1 到 seg[y],因为seg[x]其实连接的是上面一条边的边权。

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define ll long long
#define lson left, mid, rt<<1
#define rson mid + 1, right, rt<<1|1
using namespace std;
const ll maxn = 300000 + 10;
char opt[9];
ll n, m, root, res;
ll top[maxn], rev[maxn], seg[maxn], son[maxn];
ll fa[maxn], size[maxn], deep[maxn];
ll u[maxn], v[maxn], w[maxn];
ll tree[maxn<<2], lazy[maxn<<2], num, node[maxn];
struct edge{
	ll next, from, to, len;
}e[maxn<<2];
ll head[maxn], cnt;
void add(ll u, ll v, ll w)
{
	e[++cnt].from = u;
	e[cnt].len = w;
	e[cnt].next = head[u];
	e[cnt].to = v;
	head[u] = cnt;
}
//-----segment_tree-----
void PushUP(ll rt)
{
	tree[rt] = max(tree[rt<<1], tree[rt<<1|1]);
}
void build(ll left, ll right, ll rt)
{
	if(left == right)
	{
		tree[rt] = rev[left];
		return;
	}
	ll mid = (left + right)>>1;
	build(lson);
	build(rson);
	PushUP(rt);
}
void PushDOWN(ll rt)
{
	lazy[rt<<1] = lazy[rt];
	lazy[rt<<1|1] = lazy[rt];
	tree[rt<<1] = lazy[rt];
	tree[rt<<1|1] = lazy[rt];
	lazy[rt] = 0;
}
void update(ll l, ll r, ll add, ll left, ll right, ll rt)
{
	if(l <= left && r >= right)
	{
		tree[rt] = add;
		lazy[rt] = add;
		return;
	}
	ll mid = (left + right)>>1;
	if(lazy[rt]) PushDOWN(rt);
	if(l <= mid) update(l, r, add, lson);
	if(r > mid) update(l, r, add, rson);
	PushUP(rt);
}
ll query(ll l, ll r, ll left, ll right, ll rt)
{
	ll res = -0x7fffffff;
	if(l <= left && r >= right)
	{
		return tree[rt];
	}
	ll mid = (left + right)>>1;
	if(lazy[rt]) PushDOWN(rt);
	if(l <= mid) res = max(res, query(l, r, lson));
	if(r > mid) res = max(res, query(l, r, rson));
	return res;
}
//----------------------
void dfs1(ll u, ll f, ll d)
{
	ll maxson = -1;
	size[u] = 1;
	deep[u] = d;
	fa[u] = f;
	for(ll i = head[u]; i != -1; i = e[i].next)
	{
		ll v = e[i].to;
		if(f != v)
		{
			dfs1(v, u, d+1);
			size[u] += size[v];
			if(size[v] > maxson) son[u] = v, maxson = size[v];
		}
	}
}
void dfs2(ll u, ll t)
{
	seg[u] = ++num;
	rev[num] = node[u];
	top[u] = t;
	if(!son[u]) return;
	dfs2(son[u], t);
	for(ll i = head[u]; i != -1; i = e[i].next)
	{
		ll v = e[i].to;
		if(v == son[u] || v == fa[u]) continue;
		dfs2(v,v);
	}
}
void updRange(ll x, ll y, ll k)
{
    while(top[x] != top[y])
    {
        if(deep[top[x]] < deep[top[y]]) swap(x, y);
        update(seg[top[x]], seg[x], k, 1, n, 1);
        x = fa[top[x]];
    }
    if(deep[x] > deep[y]) swap(x, y);
    update(seg[x], seg[y], k, 1, n, 1);
}
ll qRange(ll x, ll y)
{
    ll ans = 0;
    while(top[x] != top[y])
    {
        if(deep[top[x]] < deep[top[y]]) swap(x, y);
        res = 0;
        res = query(seg[top[x]], seg[x], 1, n, 1);
        ans = max(res, ans);
		x = fa[top[x]];
    }
    if(deep[x] > deep[y]) swap(x, y);
    res = 0;
    res = query(seg[x]+1, seg[y], 1, n, 1);
    ans = max(res, ans);
	return ans;
}
int main()
{
	memset(head, -1, sizeof(head));
	scanf("%lld",&n);
	root = 1;
	for(ll i = 1; i < n; i++)
	{
		scanf("%lld%lld%lld",&u[i],&v[i],&w[i]);
		add(u[i],v[i],w[i]); add(v[i],u[i],w[i]);
	}
	dfs1(root, 0, 1);
	//for(int i = 1; i <= n; i++) cout<<deep[i]<<" ";
	for(ll i = 1; i < n; i++)
	{
		if(deep[u[i]] < deep[v[i]]) node[v[i]] = w[i];
		else node[u[i]] = w[i];
	}
	//for(int i = 1; i <= n; i++) cout<<node[i]<<" ";
	dfs2(root, root);
	build(1, n, 1);
	while(cin>>opt && opt[0] != 'D')
	{
		ll x, y, z;
		if(opt[0] == 'C')
		{
			scanf("%lld%lld",&x,&y);
			if(deep[u[x]] > deep[v[x]]) updRange(u[x], u[x], y);
			else updRange(v[x], v[x], y);
		}
		else
		{
			scanf("%lld%lld",&x,&y);
			if(x == y)
			{
				printf("0
");
				continue;
			}
			printf("%lld
",qRange(x,y));
		}
	}
}
原文地址:https://www.cnblogs.com/MisakaAzusa/p/9416364.html