libgdx判断矩形重叠碰撞

有两种方式。

1. 排除法，排除四种不可能重叠的情况就是了。

1     public static boolean IsOverlap( Rectangle rect1, Rectangle rect2 ){
2         float x1 = rect1.x, y1 = rect1.y, w1 = rect1.width, h1 = rect1.height;
3         float x2 = rect2.x, y2 = rect2.y, w2 = rect2.width, h2 = rect2.height; 
4         
5         return !( x1+w1<=x2 || x2+w2<=x1 || y1+h1<=y2 || y2+h2<=y1 );
6     }

2. 直接法，保证两个矩形x和y方向都有重叠。

1     public static boolean IsOverlap( Rectangle rect1, Rectangle rect2 ){
2         float x1 = rect1.x, y1 = rect1.y, w1 = rect1.width, h1 = rect1.height;
3         float x2 = rect2.x, y2 = rect2.y, w2 = rect2.width, h2 = rect2.height; 
4         
5         return x1<x2+w2 && x2<x1+w1 && y1<y2+h2 && y2<y1+h1;
6     }

两种方式都是只需要4次比较即可。