TSQL之JOIN(连接)彻底理解

T-SQL之JOIN彻底理解

本文不解释,欢迎提问解答,谢谢。直接上代码:

--测试数据建立
Create TABLE JOIN_TEST(
COLA INT,
COLB INT
)
 
GO
INSERT INTO JOIN_TEST
SELECT 1,1
 
INSERT INTO JOIN_TEST
SELECT 1,1
 
GO
--测试数据建立完毕
 
SELECT * FROM JOIN_TEST
/*
 
COLA        COLB
----------- -----------
1           1
1           1
 
(2 行受影响)
*/
 
 
SELECT * FROM JOIN_TEST A  CROSS JOIN JOIN_TEST B
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
1           1           1           1
1           1           1           1
1           1           1           1
1           1           1           1
 
(4 行受影响)
 
*/
 
 
SELECT * FROM JOIN_TEST A  INNER JOIN  JOIN_TEST B ON A.COLA=B.COLA
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
1           1           1           1
1           1           1           1
1           1           1           1
1           1           1           1
(4 行受影响)
 
*/
 
 
SELECT * FROM JOIN_TEST A  LEFT JOIN  JOIN_TEST B ON A.COLA=B.COLA
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
1           1           1           1
1           1           1           1
1           1           1           1
1           1           1           1
(4 行受影响)
 
*/
 
SELECT * FROM JOIN_TEST A  LEFT JOIN  JOIN_TEST B ON A.COLA=B.COLA AND A.COLA<>1
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
1           1           NULL        NULL
1           1           NULL        NULL
(2 行受影响)
*/
 
SELECT * FROM JOIN_TEST A  LEFT JOIN  JOIN_TEST B ON A.COLA=B.COLA WHERE A.COLA<>1
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
 
(0 行受影响)
*/
 
SELECT * FROM JOIN_TEST A  FULL JOIN  JOIN_TEST B ON A.COLA=B.COLA AND A.COLA<>1
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
1           1           NULL        NULL
1           1           NULL        NULL
NULL        NULL        1           1
NULL        NULL        1           1
*/
 
SELECT * FROM JOIN_TEST A  FULL JOIN  JOIN_TEST B ON A.COLA=B.COLA where A.COLA<>1
/*
COLA        COLB        COLA        COLB
----------- ----------- ----------- -----------
 
(0 行受影响)
*/
原文地址:https://www.cnblogs.com/Leo_wl/p/2478551.html