1083 是否存在相等的差 (20 分)

#include <iostream>
#include <cmath>
using namespace std;
int arr[1 << 20];
int main() {
    int n;
    cin >> n;
    for (int i = 1; i <= n; i++) {
        int x, t;
        cin >> x;
        t = abs(x - i);
        arr[t]++;
    }
    for (int i = 10000; i >= 0; i--) {
        if (arr[i] > 1) {. //既然是重复就一定要大于一
            cout << i << ' ' << arr[i] << endl;
        }
    }
    return 0;
}
原文地址:https://www.cnblogs.com/Hk456/p/10760106.html