C# XML反序列化解析成对象集合

1.需要解析的XML字符串

string xmlStr = @"<Request>
                     <BookedInfos>
                         <BookedInfo>
                            <CHARGECODE> 收费项编码 </CHARGECODE>
                             <HISDEPTCODE> His科室代码 </HISDEPTCODE>
                              <INQTY> 出库数量 </INQTY>
                              </BookedInfo>
                         <BookedInfo>
                               <CHARGECODE> 收费项编码 </CHARGECODE>
                               <HISDEPTCODE> His科室代码 </HISDEPTCODE>
                               <INQTY> 出库数量 </INQTY>
                         </BookedInfo>
                     </BookedInfos>
                   </Request>";

2.需要解析成的目标实体类

    public class BookedInfo
    {
        public string CHARGECODE { get; set; }
        public string HISDEPTCODE { get; set; }
        public string INQTY { get; set; }
    }

3.解析的帮助方法

public static List<T> XmlUrlConvertModel<T>(string xmlStr, string nodename) where T : class, new()
{
    List<T> ts = new List<T>();
    XmlDocument xmlDoc = new XmlDocument();
    xmlDoc.LoadXml(xmlStr);
    XmlNodeList xmlNodeList = xmlDoc.SelectNodes(nodename);
    foreach (XmlNode xnls in xmlNodeList)
    {
        T t = new T();
        if (xnls.Name.ToUpper() == typeof(T).Name.ToUpper())
        {
            foreach (XmlNode xnl in xnls.ChildNodes)
            {
                PropertyInfo[] propertyInfo = typeof(T).GetProperties(BindingFlags.Public | BindingFlags.Instance);
                foreach (PropertyInfo pinfo in propertyInfo)
                {
                    if (xnl.Name.ToUpper() == pinfo.Name.ToUpper())
                    {
                        pinfo.SetValue(t, xnl.InnerText, null);
                        break;
                    }
                }
            }
        }
        ts.Add(t);
    }
    return ts;
}

4.调用帮助方法

object obj = new object(); 
List<BookedInfo> ls = new List<BookedInfo>();
 try
 {
     ls = ObjHelper.XmlUrlConvertModel<BookedInfo>(xml, "Request/BookedInfos/BookedInfo");
 }
 catch (Exception)
 {
     obj = new { code = -1, message = "未能识别xml,请校验!" };
     return JsonConvert.SerializeObject(obj);
 }

5.结果

PS:类名和父标签相同