刷题-力扣-412. Fizz Buzz

412. Fizz Buzz

题目链接

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/fizz-buzz
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题目描述

给你一个整数 n ,找出从 1 到 n 各个整数的 Fizz Buzz 表示,并用字符串数组 answer(下标从 1 开始)返回结果,其中:

answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。
answer[i] == "Fizz" 如果 i 是 3 的倍数。
answer[i] == "Buzz" 如果 i 是 5 的倍数。
answer[i] == i 如果上述条件全不满足。

示例 1:

输入:n = 3
输出:["1","2","Fizz"]

示例 2:

输入:n = 5
输出:["1","2","Fizz","4","Buzz"]

示例 3:

输入:n = 15
输出:["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

提示:

  • 1 <= n <= 104

题目分析

  1. 根据题目描述,根据i的值向数组中填值

代码

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        std::vector<string> res;
        for (int i = 1; i <= n; ++i) {
            if (i % 3 == 0 && i % 5 == 0) { res.emplace_back(this->fizzbuzz); }
            else if (i % 3 == 0) { res.emplace_back(this->fizz); }
            else if (i % 5 == 0) { res.emplace_back(this->buzz); }
            else { res.emplace_back(std::to_string(i)); }
        }
        return res;
    }

private:
    const string fizzbuzz = "FizzBuzz";
    const string fizz = "Fizz";
    const string buzz = "Buzz";
};
原文地址:https://www.cnblogs.com/HanYG/p/15405540.html