Codeforces 864 A Fair Game 水题

  题目链接: http://codeforces.com/problemset/problem/864/A

  题目描述: 看不是是不是一串数中只有两种数且这两种数字的数量是相同的

  解题思路: 水题, 水过去

  代码: 

#include <iostream>
#include <cstdio>
#include <map>
#include <iterator>
using namespace std;

map<int, int > m;
int main() {
    int n;
    cin >> n;
    int cnt = 0;
    for( int i = 0; i < n; i++ ) {
        int num;
        cin >> num;
        if( m[num] == 0 ) cnt++;
        m[num]++;
    }
    if( cnt == 2 ) {
        map<int, int>::iterator it;
        it = m.begin();
        int temp = it->second;
        int ans = it->first;
        it++;
        if( temp == it->second ) {
            cout << "YES" << endl;
            cout << ans << " " << it->first << endl;
        }
        else {
            cout << "NO" << endl;
        }
    }
    else {
        cout << "NO" << endl;
    }
    return 0;
}
View Code

  思考: 十分钟做出来的......读题读了六分钟, 真的菜

http://codeforces.com/problemset/problem/864/A

原文地址:https://www.cnblogs.com/FriskyPuppy/p/7599179.html