leetcode:Count and Say【Python版】

一次AC

字符串就是：count+char

 1 class Solution:
 2     # @return a string
 3     def countAndSay(self, n):
 4         str = "1"
 5         for i in range(n-1):
 6             tmp = str
 7             str = ""
 8             c = tmp[0]
 9             cnt = 1
10             for j in range(1,len(tmp)):
11                 if tmp[j] == tmp[j-1]:
12                     cnt += 1
13                 else:
14                     str += ("%d"%cnt + tmp[j-1])
15                     cnt = 1
16             str += ("%d"%cnt + tmp[len(tmp)-1])
17         return str
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原文地址：https://www.cnblogs.com/CheeseZH/p/4033890.html