C++运算符优先级

在一个表达式中可能包含多个有不同运算符连接起来的、具有不同数据类型的数据对象;由于表达式有多种运算,不同的运算顺序可能得出不同结果甚至出现错误运算错误,因为当表达式中含多种运算时,必须按一定顺序进行结合,才能保证运算的合理性和结果的正确性、唯一性。
优先级从上到下依次递减,最上面具有最高的优先级,逗号操作符具有最低的优先级。表达式的结合次序取决于表达式中各种运算符的优先级。优先级高的运算符先结合,优先级低的运算符后结合,同一行中的运算符的优先级相同。
C++运算符优先级
Operator
Description
Example
Overloadable
Group 1(no associativity)
     
::
Scope resolution operator
Class::age = 2;
NO
Group 2
     
()
Function call
isdigit('1')
YES
()
Member initalization
c_tor(int x, int y) : _x(x), _y(y*10){};
YES
[]
Array access
array[4] = 2;
YES
->
Member access from a pointer
ptr->age = 34;
YES
.
Member access from an object
obj.age = 34;
NO
++
Post-increment
for( int i = 0; i < 10; i++ ) cout << i;
YES
--
Post-decrement
for( int i = 10; i > 0; i-- ) cout << i;
YES
const_cast
Special cast
const_cast<type_to>(type_from);
NO
dynamic_cast
Special cast
dynamic_cast<type_to>(type_from);
NO
static_cast
Special cast
static_cast<type_to>(type_from);
NO
reinterpret_cast
Special cast
reinterpret_cast<type_to>(type_from);
NO
typeid
Runtime type information
cout &laquo; typeid(var).name();
cout &laquo; typeid(type).name();
NO
Group 3(right-to-left associativity)
     
!
Logical negation
if( !done ) …
YES
not
Alternate spelling for !
   
~
Bitwise complement
flags = ~flags;
YES
compl
Alternate spelling for ~
   
++
Pre-increment
for( i = 0; i < 10; ++i ) cout << i;
YES
--
Pre-decrement
for( i = 10; i > 0; --i ) cout << i;
YES
-
Unary minus
int i = -1;
YES
+
Unary plus
int i = +1;
YES
*
Dereference
int data = *intPtr;
YES
&
Address of
int *intPtr = &data;
YES
new
Dynamic memory allocation
long *pVar = new long;
MyClass *ptr = new MyClass(args);
YES
new []
Dynamic memory allocation of array
long *array = new long[n];
YES
delete
Deallocating the memory
delete pVar;
YES
delete []
Deallocating the memory of array
delete [] array;
YES
(type)
Cast to a given type
int i = (int) floatNum;
YES
sizeof
Return size of an object or type
int size = sizeof floatNum;
int size = sizeof(float);
NO
Group 4
     
->*
Member pointer selector
ptr->*var = 24;
YES
.*
Member object selector
obj.*var = 24;
NO
Group 5
     
*
Multiplication
int i = 2 * 4;
YES
/
Division
float f = 10.0 / 3.0;
YES
%
Modulus
int rem = 4 % 3;
YES
Group 6
     
+
Addition
int i = 2 + 3;
YES
-
Subtraction
int i = 5 - 1;
YES
Group 7
     
<<
Bitwise shift left
int flags = 33 << 1;
YES
>>
Bitwise shift right
int flags = 33 >> 1;
YES
Group 8
     
<
Comparison less-than
if( i < 42 ) …
YES
<=
Comparison less-than-or-equal-to
if( i <= 42 ) ...
YES
>
Comparison greater-than
if( i > 42 ) …
YES
>=
Comparison greater-than-or-equal-to
if( i >= 42 ) ...
YES
Group 9
     
==
Comparison equal-to
if( i == 42 ) ...
YES
eq
Alternate spelling for ==
   
!=
Comparison not-equal-to
if( i != 42 ) …
YES
not_eq
Alternate spelling for !=
   
Group 10
     
&
Bitwise AND
flags = flags & 42;
YES
bitand
Alternate spelling for &
   
Group 11
     
^
Bitwise exclusive OR (XOR)
flags = flags ^ 42;
YES
xor
Alternate spelling for ^
   
Group 12
     
|
Bitwise inclusive (normal) OR
flags = flags | 42;
YES
bitor
Alternate spelling for |
   
Group 13
     
&&
Logical AND
if( conditionA && conditionB ) …
YES
and
Alternate spelling for &&
   
Group 14
     
||
Logical OR
if( conditionA || conditionB ) ...
YES
or
Alternate spelling for ||
   
Group 15(right-to-left associativity)
     
? :
Ternary conditional (if-then-else)
int i = (a > b) ? a : b;
NO
Group 16(right-to-left associativity)
     
=
Assignment operator
int a = b;
YES
+=
Increment and assign
a += 3;
YES
-=
Decrement and assign
b -= 4;
YES
*=
Multiply and assign
a *= 5;
YES
/=
Divide and assign
a /= 2;
YES
%=
Modulo and assign
a %= 3;
YES
&=
Bitwise AND and assign
flags &= new_flags;
YES
and_eq
Alternate spelling for &=
   
^=
Bitwise exclusive or (XOR) and assign
flags ^= new_flags;
YES
xor_eq
Alternate spelling for ^=
   
|=
Bitwise normal OR and assign
flags |= new_flags;
YES
or_eq
Alternate spelling for |=
   
<<=
Bitwise shift left and assign
flags <<= 2;
YES
>>=
Bitwise shift right and assign
flags >>= 2;
YES
Group 17
     
throw
throw exception
throw EClass(“Message”);
NO
Group 18
     
,
Sequential evaluation operator
for( i = 0, j = 0; i < 10; i++, j++ ) …
YES

 

作者:耑新新,发布于  博客园

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原文地址:https://www.cnblogs.com/Arthurian/p/9020428.html