对象根据里面的某一个属性合并

后端返回的数据，前端需要根据对象里的某个属性合并相同的属性

方法一：

let array = [
        { key: "a", value: "2" },
        { key: "a", value: "2" },
        { key: "a", value: "2" },
        { key: "b", value: "8" }
         ];
      let result = {};
      array.forEach((item) => {
        if (result[item.key]) {
          result[item.key] += Number(item.value);
        } else {
          result[item.key] = Number(item.value);
        }
      });
      let s = [];
      for (let k in result) {
        s.push({ key: k, value: result[k] });
      }
      console.log(s);

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  ****方法二：****

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let abc=[
      {typeid:"韩元",ade:1},
      {typeid:"人民币",ade:10000},
      {typeid:"人民币",ade:200000},
      {typeid:"美元",ade:200},
      {typeid:"美元",ade:200},
  ]
  let result={};
  for(let i=0;i<abc.length;i++){
      if(result[abc[i].typeid]){
          result[abc[i].typeid]+=abc[i].ade;
      }else{
          result[abc[i].typeid]=abc[i].ade;
      }
  }
  console.log(result)
  var keyvalue=[];
  for(var key in result){
      keyvalue.push({typeid:key,adelenth:result[key]})
  }
  console.log(keyvalue)

转自于：https://blog.csdn.net/weixin_48645836/article/details/106756056?utm_medium=distribute.pc_relevant.none-task-blog-utm_term-2&spm=1001.2101.3001.4242