P1563 玩具谜题(简单模拟)

就是一个简单模拟

#include<iostream>
#include<string>
using namespace std;
const int maxn=1e5+10;
int in[maxn], x[maxn], y[maxn];
string name[maxn];
int h;

int n, m;
int main(){
    cin>>n>>m;
    for(int i=0;i<n;++i)cin>>in[i]>>name[i];
    for(int i=0;i<m;++i)cin>>x[i]>>y[i];
    h=0;
    for(int i=0;i<m;++i){
        if(in[h]==0){
            if(x[i]==0)h-=y[i];
            else h+=y[i];
            h%=n; h=(h+n)%n;
        }else{
             if(x[i]==0)h+=y[i];
            else h-=y[i];
            h%=n; h=(h+n)%n;
        }
    }
    cout<<name[h]<<endl;
}
原文地址:https://www.cnblogs.com/ALINGMAOMAO/p/10686286.html