【leetcode刷题】mysql题库

IFNULL(exp1, exp2)

如果存在exp1则展示exp1,如果没有输出exp2

cast

convert 

# Write your MySQL query statement below
select DISTINCT
Num as ConsecutiveNums
from
(
select
Num,
( CASE WHEN Num = @curNum THEN @counter := @counter + 1 WHEN @curNum :=Num THEN @counter := 1 END ) as counter
from
Logs,
( select @curNum := NULL, @counter := 0 ) as q
) as a
where
counter >= 3

https://www.cnblogs.com/dannylinux/articles/8288790.html

原文地址:https://www.cnblogs.com/AHappyBird/p/10574080.html