python 字典 按照value排序

ret_top = {'111':20,'222':1,'233':5}
ret = sorted(ret_top.items(), key=lambda e: e[1], reverse=True)
print(ret) # [('111', 20), ('233', 5), ('222', 1)]
原文地址:https://www.cnblogs.com/412013cl/p/8822198.html