UVA-297 Quadtrees (四分树)

题目大意:求将两个以四分树形式给出的大方格合并后的小黑方格的个数。

题目分析:比较简单的四分树。

代码如下:

# include<iostream>
# include<cstdio>
# include<cstring>
# include<algorithm>
using namespace std;

char p[1000];
int mark[35][35],ans;

void draw(int &cur,int r,int c,int w)///参数为引用保证递归进行到底
{
    char ch=p[cur++];
    if(ch=='p'){
        draw(cur,r,c+w/2,w/2);
        draw(cur,r,c,w/2);
        draw(cur,r+w/2,c,w/2);
        draw(cur,r+w/2,c+w/2,w/2);
    }else if(ch=='f'){
        for(int i=r;i<r+w;++i)
            for(int j=c;j<c+w;++j)
                if(!mark[i][j])
                    mark[i][j]=1,++ans;
    }
}

int main()
{
    int T;
    scanf("%d",&T);
    while(T--)
    {
        memset(mark,0,sizeof(mark));
        ans=0;
        for(int i=0;i<2;++i){
            int t=0;
            scanf("%s",p);
            draw(t,0,0,32);
        }
        printf("There are %d black pixels.
",ans);
    }
    return 0;
}

  

原文地址:https://www.cnblogs.com/20143605--pcx/p/4858454.html