PAT甲级——A1065 A+B and C (64bit)

Given three integers A, B and C in [−], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where Xis the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include <iostream>
using namespace std;
long long N, A, B, C, sum;
int main()
{
    cin >> N;
    for (int i = 1; i <= N; ++i)
    {
        cin >> A >> B >> C;
        sum = A + B;
        if (A > 0 && B > 0 && sum < 0)//正溢出
            cout << "Case #" << i << ": " << "true" << endl;
        else if (A < 0 && B < 0 && sum >= 0)//负溢出
            cout << "Case #" << i << ": " << "false" << endl;
        else if(sum>C)
            cout << "Case #" << i << ": " << "true" << endl;
        else
            cout << "Case #" << i << ": " << "false" << endl;
    }
    return 0;
}