题意：给你字符串，两种模式，每一种模式有相应规则的不同意思，问你这个字符串一共有多少意思
解题思路：合在一起两种模式暴力
解题代码：
1 // File Name: 1005.cpp 2 // Author: darkdream 3 // Created Time: 2014年07月29日 星期二 15时54分08秒 4 5 #include<vector> 6 #include<list> 7 #include<map> 8 #include<set> 9 #include<deque> 10 #include<stack> 11 #include<bitset> 12 #include<algorithm> 13 #include<functional> 14 #include<numeric> 15 #include<utility> 16 #include<sstream> 17 #include<iostream> 18 #include<iomanip> 19 #include<cstdio> 20 #include<cmath> 21 #include<cstdlib> 22 #include<cstring> 23 #include<ctime> 24 25 using namespace std; 26 #define LL long long 27 LL ans = 0 ; 28 char str1[1000000]; 29 char str[10000000]; 30 int main(){ 31 int n; 32 while(scanf("%d",&n) != EOF) 33 { 34 int len = 0; 35 getchar(); 36 for(int i =1 ;i <= n;i ++) 37 { 38 // printf("%d ",i); 39 gets(str1); 40 int len1 = strlen(str1); 41 // printf("%d ",len1); 42 for(int j = 0 ;j < len1 ;j++) 43 str[j+len] = str1[j]; 44 len = len + len1; 45 } 46 int is = 0 ; 47 ans = 1; 48 int t = 0 ; 49 LL tans = 1 ; 50 int ok = 0 ; 51 for(int i = 0 ;i < len ;i ++) 52 { 53 if(ok == 1) 54 break; 55 if(is) 56 { 57 if(str[i] == ' ') 58 { 59 t++; 60 if(str[i+1] != ' ') 61 { 62 tans *=(t+1); 63 t = 0 ; 64 } 65 }else if(str[i] == '$'){ 66 is = 0 ; 67 ans = tans * ans; 68 tans = 1; 69 } 70 if(ans > 100000 || tans > 100000) 71 { 72 ok = 1; 73 } 74 }else { 75 // printf("**** "); 76 if(str[i] == '{') 77 { 78 // printf("**** "); 79 int t = 1 ; 80 int j ; 81 for(j = i +1; ;j ++) 82 { 83 if(str[j] == '}') 84 break; 85 if(str[j] == '|') 86 t ++ ; 87 } 88 i = j; 89 ans *= t ; 90 if(ans > 100000) 91 { 92 ok = 1; 93 } 94 }else{ 95 if(str[i] == '$') 96 is = 1; 97 } 98 } 99 // printf("%I64d %d ",ans,i); 100 } 101 if(ans > 100000 || ok ) 102 printf("doge "); 103 else 104 printf("%I64d ",ans); 105 } 106 return 0; 107 }