UVa 11991 一道简单题

https://vjudge.net/problem/UVA-11991

题意：
给出一个包含n个整数的数组，你需要回答若干询问。每次询问两个整数k和v，输出从左到右第k个v的下标。

思路：

把每个数字所出现的下标存储在vector中。

 1 #include<iostream>
 2 #include<string>
 3 #include<cstring>
 4 #include<algorithm>
 5 #include<vector>
 6 #include<map>
 7 using namespace std;
 8 
 9 const int maxn = 1000000 + 5;
10 
11 int n, m;
12 vector<int> s[maxn];
13 
14 int main()
15 {
16     //freopen("D:\txt.txt", "r", stdin);
17     while (cin >> n >> m)
18     {
19         int x;
20         for (int i = 0; i < maxn; i++)
21             s[i].clear();
22         for (int i = 1; i <= n; i++)
23         {
24             cin >> x;
25             s[x].push_back(i);
26         }
27         int k, v;
28         for (int i = 0; i < m; i++)
29         {
30             cin >> k >> v;
31             if (k <= s[v].size())  cout << s[v][k - 1] << endl;
32             else cout << '0' << endl;
33         }
34     }
35 }

刘汝佳的做法更妙一些。

#include<iostream>
#include<string>
#include<cstring>
#include<algorithm>
#include<vector>
#include<map>
using namespace std;

int n, m;
map <int, vector<int> > a;

int main()
{
    //freopen("D:\txt.txt", "r", stdin);
    while (cin >> n >> m)
    {
        a.clear();
        int x;
        for (int i = 1; i <= n; i++)
        {
            cin >> x;
            if (!a.count(x))   a[x] = vector<int>();
            a[x].push_back(i);
        }
        int k, v;
        for (int i = 0; i < m; i++)
        {
            cin >> k >> v;
            if (k <= a[v].size())    cout << a[v][k - 1] << endl;
            else cout << '0' << endl;
        }
    }
}