ZOJ 3869 Ace of Aces

There is a mysterious organization called Time-Space Administrative Bureau (TSAB) in the deep universe that we humans have not discovered yet. This year, the TSAB decided to elect an outstanding member from its elite troops. The elected guy will be honored with the title of "Ace of Aces".

After voting, the TSAB received N valid tickets. On each ticket, there is a number A_i denoting the ID of a candidate. The candidate with the most tickets nominated will be elected as the "Ace of Aces". If there are two or more candidates have the same number of nominations, no one will win.

Please write program to help TSAB determine who will be the "Ace of Aces".

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

The first line contains an integer N (1 <= N <= 1000). The next line contains N integers A_i (1 <= A_i <= 1000).

Output

For each test case, output the ID of the candidate who will be honored with "Ace of Aces". If no one win the election, output "Nobody" (without quotes) instead.

Sample Input

Sample Output

2
Nobody
998
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2015浙江省赛的题目其中一题，不是很难。
题意：给出n张选票，算出得票数最多的人的id，如果有2个及以上的人都获得了最多的选票，则输出Nobody。
思路：计数题。设一个结构体，最后按照票数来排序即可。

#include<iostream>
#include<string>
#include<cstring>
#include<algorithm>
using namespace std;

struct node
{
    int id;
    int cnt;
}a[1005];

bool cmp(node a, node b)
{
    return a.cnt > b.cnt;
}

int main()
{
    //freopen("D:\txt.txt", "r", stdin);
    int n;
    while (cin >> n)
    {
        while (n--)
        {
            memset(a, 0, sizeof(a));
            int t,m;
            int maxn = 0;
            cin >> t;
            for (int i = 0; i < t; i++)
            {
                cin >> m;
                a[m].id = m;
                a[m].cnt++;
            }
            sort(a, a + 1000, cmp);
            if (a[0].cnt == a[1].cnt)  cout << "Nobody" << endl;
            else cout << a[0].id<<endl;
        }
    }
}