CF1101C Division and Union 线段相交问题

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<bitset>
#include<ctime>
#include<deque>
#include<stack>
#include<functional>
#include<sstream>
//#include<cctype>
//#pragma GCC optimize(2)
using namespace std;
#define maxn 100005
#define inf 0x7fffffff
//#define INF 1e18
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
#define rdult(x) scanf("%lu",&x)
#define rdlf(x) scanf("%lf",&x)
#define rdstr(x) scanf("%s",x)
typedef long long  ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const long long int mod = 1e9 + 7;
#define Mod 1000000000
#define sq(x) (x)*(x)
#define eps 1e-4
typedef pair<int, int> pii;
#define pi acos(-1.0)
//const int N = 1005;
#define REP(i,n) for(int i=0;i<(n);i++)
typedef pair<int, int> pii;
inline ll rd() {
    ll x = 0;
    char c = getchar();
    bool f = false;
    while (!isdigit(c)) {
        if (c == '-') f = true;
        c = getchar();
    }
    while (isdigit(c)) {
        x = (x << 1) + (x << 3) + (c ^ 48);
        c = getchar();
    }
    return f ? -x : x;
}

ll gcd(ll a, ll b) {
    return b == 0 ? a : gcd(b, a%b);
}
int sqr(int x) { return x * x; }


/*ll ans;
ll exgcd(ll a, ll b, ll &x, ll &y) {
    if (!b) {
        x = 1; y = 0; return a;
    }
    ans = exgcd(b, a%b, x, y);
    ll t = x; x = y; y = t - a / b * y;
    return ans;
}
*/

int T;
int n;
struct node {
    int l, r;
    bool operator<(const node&rhs)const {
        if (l < rhs.l)return true;
        if (l > rhs.l)return false;
        if (l == rhs.l)return r < rhs.r;
    }
}line[maxn];
int l[maxn], r[maxn];

int main() {
    //ios::sync_with_stdio(0);
    rdint(T);
    while (T--) {
        rdint(n);
        for (int i = 1; i <= n; i++) {
            rdint(l[i]); rdint(r[i]);
            line[i].l = l[i]; line[i].r = r[i];
        }
        sort(line + 1, line + 1 + n);
        bool fg = false;
        int R = -1;
        for (int i = 1; i <= n; i++) {
            if (i == 1)R = line[i].r;
            if (line[i].l > R) {
                fg = true; break;
            }
            else R = max(R, line[i].r);
        }
        if (!fg) {
            cout << -1 << endl;
        }
        else {
            for (int i = 1; i <= n; i++) {
                if (r[i] <= R) {
                    cout << 1 << ' ';
                }
                else cout << 2 << ' ';
            }
            cout << endl;
        }
    }
    return 0;
}
EPFL - Fighting
原文地址:https://www.cnblogs.com/zxyqzy/p/10275723.html