将字符串str1复制为字符串str2的三种解决方法

http://www.jb51.net/article/42165.htm
1.自己编写函数,将两个字符串进行复制

#include<iostream>
using namespace std;
int main(){
   char str1[]="I love China!",str2[20];
   void Strcpy(char *p1,char *p2);
   Strcpy(str2,str1);
   cout<<"str1: "<<str1<<endl;
   cout<<"str2: "<<str2<<endl;
   return 0;
}
void Strcpy(char *p2,char *p1){
 int i=0;
 for(;*p1!='';p1++,p2++){
  *p2=*p1;
 }
 *p2='';
}

2.使用函数库重的strcpy函数

#include<iostream>
#include<string.h>
using namespace std;
int main()
{
    char str1[]="I love China!",str2[20];
    strcpy(str2,str1);
    cout<<"str1: "<<str1<<endl;
    cout<<"str2: "<<str2<<endl;
    return 0;
}

3.定义两个字符串变量,然后直接进行赋值

#include<iostream>
#include<string>
using namespace std;
int main(){
   string str1="I love China!",str2;
   str2=str1;
   cout<<"str1: "<<str1<<endl;
   cout<<"str2: "<<str2<<endl;
   return 0;
}
原文地址:https://www.cnblogs.com/zxy160/p/7215110.html