字典排序

dicts = {'zhang':22,'wang':44,'li':31,'zhao':27}
s = sorted(dicts.items(),key=lambda x:x[0])
print(s)
ss = sorted(dicts.items(), key=lambda x:x[1])
print(ss)
原文地址:https://www.cnblogs.com/zxt-cn/p/9714885.html