AtCoder Beginner Contest 079 D

AtCoder Beginner Contest 079 D - Wall

 Warshall Floyd 最短路。。。。先枚举 k

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 int c[10][10];
 7 int H, W, A, ans;
 8 
 9 int main()
10 {
11     scanf("%d%d", &H, &W);
12     for (int i = 0; i < 10; i++)
13         for (int j = 0; j < 10; j++)
14             scanf("%d", &c[i][j]);
15     for(int k=0;k<10;k++)
16         for(int i=0;i<10;i++)
17             for (int j = 0; j < 10; j++) {
18                 if (c[i][j] > c[i][k] + c[k][j])
19                     c[i][j] = c[i][k] + c[k][j];
20             }
21     ans = 0;
22     for(int i=0;i<H;i++)
23         for (int j = 0; j < W; j++) {
24             scanf("%d", &A);
25             if (A >= 0)
26                 ans += c[A][1];
27         }
28     printf("%d
", ans);
29     return 0;
30 }
原文地址:https://www.cnblogs.com/zxhyxiao/p/7871053.html