在一个有序数组中,查找具体的某个数字k

#define _CRT_SECURE_NO_WARNINGS 1

#include<stdio.h>
int main() {
int arr[] = { 1,2,3,4,5,6,7,8,9,10 };
int k = 7;

int sz = sizeof(arr) / sizeof(arr[0]);//计算元数个数
int left = 0;//左下标
int right = sz - 1;//右下标

while (left <= right)
{
int mid = (left + right) / 2;
if (arr[mid] < k)
{
left = mid + 1;
}
else if (arr[mid] > k)
{
right = mid - 1;
}
else
{
printf("找到了,这个元素的下标是:%d ", mid);
break;
}
}
if (left > right)
{
printf("这个元素不存在 ");
}
return 0;
}

原文地址:https://www.cnblogs.com/zwf020107/p/14496210.html