PAT (Advanced Level) 1113. Integer Set Partition (25)

简单题。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std;

long long a[100000+10];
long long sum=0,sum2;
int n;

int main()
{
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
    {
        scanf("%lld",&a[i]);
        sum=sum+a[i];
    }
    sort(a+1,a+1+n);
    for(int i=1;i<=n/2;i=i+1)  sum2=sum2+a[i];
    if(n%2==0) printf("0 %lld
",abs(2*sum2-sum));
    else printf("1 %lld
",abs(2*sum2-sum));
    return 0;
}
原文地址:https://www.cnblogs.com/zufezzt/p/5645058.html