PAT (Advanced Level) 1091. Acute Stroke (30)

BFS求连通块。递归会爆栈。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<map>
#include<queue>
#include<stack>
#include<vector>
using namespace std;

int M,N,L,T;
int A[70][1300][133];
bool f[70][1300][133];

int dir[10][5]={
    {0,0,1},
    {0,0,-1},
    {0,1,0},
    {0,-1,0},
    {1,0,0},
    {-1,0,0}
};

struct Point
{
    int a,b,c;
    Point (int aa,int bb,int cc)
    {
        a=aa; b=bb; c=cc;
    }
};

int Find(int a,int b,int c)
{
    int res=0;
    queue<Point>q;

    Point p(a,b,c);
    q.push(p);
    f[a][b][c]=1;

    while(!q.empty())
    {
        res++;
        Point head=q.front(); q.pop();
        for(int i=0;i<6;i++)
        {
            int na=head.a+dir[i][0];
            int nb=head.b+dir[i][1];
            int nc=head.c+dir[i][2];

            if(na>L||na<1) continue;
            if(nb>M||nb<1) continue;
            if(nc>N||nc<1) continue;

            if(A[na][nb][nc]==0) continue;
            if(f[na][nb][nc]==1) continue;

            Point p(na,nb,nc);
            q.push(p);
            f[na][nb][nc]=1;
        }
    }
    return res;
}

int main()
{
    memset(A,0,sizeof A);
    memset(f,0,sizeof f);
    scanf("%d%d%d%d",&M,&N,&L,&T);
    for(int k=1;k<=L;k++)
        for(int i=1;i<=M;i++)
            for(int j=1;j<=N;j++)
                scanf("%d",&A[k][i][j]);
    int sum=0;
    for(int k=1;k<=L;k++)
        for(int i=1;i<=M;i++)
            for(int j=1;j<=N;j++)
            {
                if(A[k][i][j]==0) continue;
                if(f[k][i][j]==1) continue;
                int res=Find(k,i,j);
                if(res>=T) sum=sum+res;
            }
    printf("%d
",sum);

    return 0;
}
原文地址:https://www.cnblogs.com/zufezzt/p/5641645.html