PAT (Advanced Level) 1058. A+B in Hogwarts (20)

简单题。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;

int a1,b1,c1;
int a2,b2,c2;
int ans1,ans2,ans3;

int main()
{
  scanf("%d.%d.%d",&a1,&b1,&c1);
  scanf("%d.%d.%d",&a2,&b2,&c2);
  
  int k;
  ans3=(c1+c2)%29;
  k=(c1+c2)/29;
  
  ans2=(b1+b2+k)%17;
  k=(b1+b2+k)/17;
  
  ans1=(a1+a2+k);
  
  printf("%d.%d.%d
",ans1,ans2,ans3);
  return 0;
}
原文地址:https://www.cnblogs.com/zufezzt/p/5551027.html