hdu 1285 确定比赛名次

简单的拓扑排序,每次都找到入度为0的节点输出,这个节点出发的连到的节点入度都减1。第一次写拓扑排序,还需改进。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<algorithm>
using namespace std;
int rudu[505];
vector<int>abc[505];
int main()
{
    int n, m, i, x, y, j, k;
    while (~scanf("%d%d", &n, &m))
    {
        memset(rudu, 0, sizeof(rudu));
        for (i = 0; i < 504; i++) abc[i].clear();
        for (i = 0; i < m; i++)
        {
            scanf("%d%d", &x, &y);
            rudu[y]++;
            abc[x].push_back(y);
        }
        for (i = 1; i <= n; i++)
        {
            for (j = 1; j <= n; j++)
            {
                if (rudu[j] == 0)
                {
                    if (i < n) printf("%d ", j);
                    else printf("%d
", j);
                    rudu[j]--;
                    for (k = 0; k < abc[j].size(); k++) rudu[abc[j][k]]--;
                    break;
                }
            }
        }
    }
    return 0;
}
原文地址:https://www.cnblogs.com/zufezzt/p/4437318.html