C language——convert ip address string into uint in linux



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  1. #include <stdio.h>
  2. #include <string.h>
  3. #include <arpa/inet.h>

  4. uint32_t ip2uint(const char *ip) {
  5.     int a, b, c, d;
  6.     uint32_t addr = 0;

  7.     if (sscanf(ip, "%d.%d.%d.%d", &a, &b, &c, &d) != 4)
  8.        return 0;

  9.     addr = a << 24;
  10.     addr |= b << 16;
  11.     addr |= c << 8;
  12.     addr |= d;
  13.     return addr;
  14. }

  15. int main()
  16. {
  17.     printf("%u ", ip2uint("0.0.0.0"));
  18.     printf("%u ", ip2uint("1.0.0.1"));
  19.     printf("%u ", ip2uint("222.202.55.66"));
  20.     printf("%u ", ip2uint("255.255.255.255"));

  21.     FILE *fp1;
  22.     char c;
  23.     fp1= fopen ("ctrl.txt", "r");
  24.     c = fgetc(fp1);
  25.     printf("%c ", c);
  26.     fclose(fp1);
  27. }



[root@localhost 桌面]# gcc tmp.c -o tmp
[root@localhost 桌面]# ./tmp
0
16777217
3737794370
4294967295
[root@localhost 桌面]#


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原文地址:https://www.cnblogs.com/ztguang/p/12649495.html