Implement Queue using Stacks(用栈实现队列)

Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.
Notes:
  • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is empty operations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

  • 题目解析:
  • 用堆栈stack实现队列,仅仅能使用堆栈的操作,push(),pop()。empty().

  • 方法:
  • 用两个堆栈实现。代码例如以下:
  • class Queue {
    public:
        stack<int> st1;
        stack<int> st2;
        bool st1_use=1;  
        bool st2_use=0;  
        // Push element x to the back of queue.
        void push(int x) {
            if(st1_use==1)
            st1.push(x);
            else if(st2_use==1)
            st2.push(x);
        }
    
        // Removes the element from in front of queue.
        void pop(void) {
            if(st1.empty()&&st2.empty())  
            exit(0);
            if(st1_use==1&&st2_use==0)
            {
                while(st1.size()>1)
                {
                    int temp=st1.top();
                    st2.push(temp);
                    st1.pop();
                }
                st1.pop();
    			while(st2.size()>0)
                {
                    int temp=st2.top();
                    st1.push(temp);
                    st2.pop();
                }
                st1_use==1;
                st2_use==0;
    			return;
            }
            if(st1_use==0&&st2_use==1)
            {
                while(st2.size()>1)
                {
                    int temp=st2.top();
                    st1.push(temp);
                    st2.pop();
                }
                st2.pop();
    			while(st1.size()>0)
                {
                    int temp=st1.top();
                    st2.push(temp);
                    st1.pop();
                }
                st1_use==0;
                st2_use==1;
    			return;
            }
        }
    
        // Get the front element.
        int peek(void) {
            if(st1_use==1&&st2_use==0)
            {
    			int temp;
                while(st1.size()>0)
                {
                    temp=st1.top();
                    st2.push(temp);
                    st1.pop();
                }
    			
    			while(st2.size()>0)
                {
                    int temp1=st2.top();
                    st1.push(temp1);
                    st2.pop();
                }
                st1_use==1;
                st2_use==0;
    			return temp;
            }
            if(st1_use==0&&st2_use==1)
            {
    			int temp;
                while(st2.size()>0)
                {
                    int temp=st2.top();
                    st1.push(temp);
                    st2.pop();
                }
    			
    			while(st1.size()>0)
                {
                    int temp1=st1.top();
                    st2.push(temp1);
                    st1.pop();
                }
                st1_use==0;
                st2_use==1;
    			return temp;
            }
        }
    
        // Return whether the queue is empty.
        bool empty(void) {
            if(st1_use==1&&st1.empty())
            return true;
            if(st2_use==1&&st2.empty())
            return true;
            return false;
        }
    
    };


原文地址:https://www.cnblogs.com/zsychanpin/p/6803119.html