欧拉回路/路径——2020-camp-day2-H

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int M =2e6+7;
int head[M],cnt;
struct EDGE{int to,nxt;}ee[M*2];
void add(int x,int y){ee[++cnt].nxt=head[x],ee[cnt].to=y,head[x]=cnt;}
int st[M],ans[M];
bool vis[M];
ll top,t;
ll len;
void euler()
{
    st[++top]=1;
    while(top>0)
    {
        int x=st[top],i=head[x];
        while(i&&vis[i])i=ee[i].nxt;
        if(i)
        {
            st[++top]=ee[i].to;
            vis[i]=vis[i^1]=true;
            head[x]=ee[i].nxt;
        }
        else 
        {
            top--;
            ans[++t]=x;
        }
    }
}
void gao(ll n,ll m)
{
    printf("%lld
",n);
    cnt=1;
    for(int i=1;i<=n;i++)
    for(int j=i+1;j<=n;j++)
    add(i,j),add(j,i);
    if(n%2==0)
    {
        for(int i=1;i<=n;i+=2)
        add(i,i+1),add(i+1,i);
    }
    euler();
    int tt=0;
    for(int i=t;i>2;i--)printf("%d ",ans[i]),tt++;
    if(tt==len-1)
        printf("%d
",ans[2]);
    else
    {
        printf("%d ",ans[2]);tt++;
        for(int i=tt+1;i<len;i++)printf("1 ");
        printf("1
");
    }
}

bool ck(ll x)
{
    ll nm=0;
    if(x&1)nm=x*(x-1)/2;
    else nm=x*(x-1)/2+x/2-1;
//    printf("===   %lld    %lld  %lld
",x,nm,len);
    if(nm<len)return true;
    else return false;
}
int main()
{
    scanf("%lld",&len);
    if(len==1)
    {
        puts("1");
        puts("1");
        return 0;
    }
    ll L=1,R=1500000000,n=0;//图上点数的界限
    while(L<=R)
    {
    //    printf("%lld  %lld
",L,R);
        ll mid=(L+R)/2;
        if(ck(mid))n=mid,L=mid+1;
        else R=mid-1;
    }
//    cout<<n<<"--  "<<endl;
    ll m=(n&1)?(n*(n-1)/2):(n*(n-1)/2+n/2-1);
    if(len>(ll)2e6){
        printf("%lld
",n);
        return 0;
    }
    gao(n,m);
//    else cout<<n<<"  "<<m<<endl;
    //n个点 m条边 
    return 0;
    
}
原文地址:https://www.cnblogs.com/zsben991126/p/12197497.html