php计算两个坐标直线距离

 1 function rad($d)
 2 {
 3        return $d * 3.1415926535898 / 180.0;
 4 }
 5 function GetDistance($lat1, $lng1, $lat2, $lng2)
 6 {
 7     $EARTH_RADIUS = 6378.137;
 8     $radLat1 = rad($lat1);
 9     //echo $radLat1;
10    $radLat2 = rad($lat2);
11    $a = $radLat1 - $radLat2;
12    $b = rad($lng1) - rad($lng2);
13    $s = 2 * asin(sqrt(pow(sin($a/2),2) +
14     cos($radLat1)*cos($radLat2)*pow(sin($b/2),2)));
15    $s = $s *$EARTH_RADIUS;
16    $s = round($s * 10000) / 10000;
17    return $s;
18 }
原文地址:https://www.cnblogs.com/zonglonglong/p/4062118.html