154. Find Minimum in Rotated Sorted Array II

    /*
     * 154. Find Minimum in Rotated Sorted Array II
     * 2016-6-1 by Mingyang
     * 只用比end,当中间和上面相等end就--
     */

     //这里笔者仅仅在I的基础上改动了两笔就通过了,所以这个是非常棒的
     public int findMin1(int[] nums) {
            int start = 0;
            int end = nums.length - 1;
            int mid = 0;
            while(start < end) {
                mid = start + (end - start) / 2;
                if (nums[mid] > nums[end]) {
                    start = mid + 1;
                }
                else if (nums[mid] < nums[end]) {
                    end = mid;
                }
                else { // when num[mid] and num[hi] are same
                    end--;
                }
            }
            return nums[start];
        }
原文地址:https://www.cnblogs.com/zmyvszk/p/5552583.html