codefoeces 864B

Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string s consisting only of lowercase and uppercase Latin letters.

Let A be a set of positions in the string. Let's call it pretty if following conditions are met:

letters on positions from A in the string are all distinct and lowercase;
there are no uppercase letters in the string which are situated between positions from A (i.e. there is no such j that s[j] is an uppercase letter, and a1 < j < a2 for some a1 and a2 from A).

Write a program that will determine the maximum number of elements in a pretty set of positions.

Input

The first line contains a single integer n (1 ≤ n ≤ 200) — length of string s.

The second line contains a string s consisting of lowercase and uppercase Latin letters.

Output

Print maximum number of elements in pretty set of positions for string s.

Examples

input

11
aaaaBaabAbA

output

input

12
zACaAbbaazzC

output

input

3
ABC

output

Note

In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.

In the second example desired positions can be 7, 8 and 11. There are other ways to choose pretty set consisting of three elements.

In the third example the given string s does not contain any lowercase letters, so the answer is 0.

这道题一直理解不了题意，看了代码才知道到底啥意思。

就是先找出每一段小写字母里的不同元素有多少个，再输出其中最大那一段的值。

#include<cstdio>
#include<cmath>
#include<iostream>
#include<vector>
#include<set>
#include<sstream>
#include<algorithm>
#include<string>
#include <cstring>
using namespace std;
const int maxn = 111;
int nu[maxn];
set<int> st;
string s;
int main() {
    ios::sync_with_stdio(false);
    int n;
    int maxx = 0;
    cin>>n>>s;
    s+="A";
    for(int i = 0; i <= n; i++) {
       // cout<<st.size()<<endl;
        if(s[i] >= 'a' && s[i] <= 'z') st.insert(s[i]);
        else maxx = max(maxx,(int)st.size()),st.clear();
    }
    cout<<maxx<<endl;
    return 0;
    
}