https://pintia.cn/problem-sets/994805342720868352/problems/994805429018673152
Given two strings S~1~ and S~2~, S = S~1~ - S~2~ is defined to be the remaining string after taking all the characters in S~2~ from S~1~. Your task is simply to calculate S~1~ - S~2~ for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S~1~ and S~2~, respectively. The string lengths of both strings are no more than 10^4^. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S~1~ - S~2~ in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
代码:
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 10; char s1[maxn], s2[maxn]; int main() { cin.getline(s1, maxn); cin.getline(s2, maxn); int len1 = strlen(s1), len2 = strlen(s2); for(int i = 0; i < len1; i ++) { for(int j = 0; j < len2; j ++) { if(s1[i] == s2[j]) s1[i] = '*'; } } for(int i = 0; i < len1; i ++) { if(s1[i] != '*') printf("%c", s1[i]); } printf(" "); return 0; }