PAT 甲级 1142 Maximal Clique

https://pintia.cn/problem-sets/994805342720868352/problems/994805343979159552

A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the clique are adjacent. A maximal clique is a clique that cannot be extended by including one more adjacent vertex. (Quoted from https://en.wikipedia.org/wiki/Clique_(graph_theory))

Now it is your job to judge if a given subset of vertices can form a maximal clique.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers Nv (≤ 200), the number of vertices in the graph, and Ne, the number of undirected edges. Then Ne lines follow, each gives a pair of vertices of an edge. The vertices are numbered from 1 to Nv.

After the graph, there is another positive integer M (≤ 100). Then M lines of query follow, each first gives a positive number K (≤ Nv), then followed by a sequence of K distinct vertices. All the numbers in a line are separated by a space.

Output Specification:

For each of the M queries, print in a line Yes if the given subset of vertices can form a maximal clique; or if it is a clique but not a maximal clique, print Not Maximal; or if it is not a clique at all, print Not a Clique.

Sample Input:

8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
3 4 3 6
3 3 2 1

Sample Output:

Yes
Yes
Yes
Yes
Not Maximal
Not a Clique

代码:

#include <bits/stdc++.h>
using namespace std;

int N, M, K;
int mp[220][220];
int vis[220];

int main() {
    scanf("%d%d", &N, &M);
    memset(mp, 0, sizeof(mp));
    while(M --) {
        int a, b;
        scanf("%d%d", &a, &b);
        mp[a][b] = mp[b][a] = 1;
    }
    scanf("%d", &K);
    while(K --) {
        int T;
        vector<int> v;
        memset(vis, 0, sizeof(vis));
        scanf("%d", &T);
        v.resize(T);
        for(int i = 0; i < T; i ++) {
            scanf("%d", &v[i]);
            vis[v[i]] = 1;
        }

        bool isclique = true;
        for(int i = 0; i < T - 1; i ++) {
            for(int j = i + 1; j < T; j ++) {
                if(mp[v[i]][v[j]] == 0) {
                    isclique = false;
                    printf("Not a Clique
");
                    break;
                }
            }
            if(!isclique) break;
        }

        if(!isclique) continue;

        bool ismax = true;
        for(int i = 1; i <= N; i ++) {
            if(vis[i] == 0) {
                for(int j = 0; j < T; j ++) {
                    if(mp[v[j]][i] == 0) break;
                    if(j == T - 1) ismax = false;
                }
            }
            if(!ismax) {
                printf("Not Maximal
");
                break;
            }
        }
        if(ismax) printf("Yes
");
    }
    return 0;
}

  简单图论

FHFHFH

原文地址:https://www.cnblogs.com/zlrrrr/p/10337315.html