c# 求第30位数的值

1,1,2,3,5,8,13,21,34,55....

求第30位数的值:

递归方法:

 1    class Program
 2     {
 3         static void Main(string[] args)
 4         {
 5             //找规律:
 6             //1,1,2,3,5,8,13,21,34,55,......
 7             int num = 30;
 8             Console.WriteLine(GetNum(30));
 9             Console.ReadKey();
10         }
11         /// <summary>
12         /// 求第30位数的值
13         /// </summary>
14         /// <param name="i"></param>
15         /// <returns></returns>
16         private static int GetNum(int i)
17         {
18             if (i<=0)
19             {
20                 return 0;
21             }else if (i>0 && i<=2)
22             {
23                 return 1;
24             }
25             else
26             {
27                 return GetNum(i - 1) + GetNum(i - 2);
28             }
29         }
30 
31     }
View Code

还有没有其他方法,请评论?

原文地址:https://www.cnblogs.com/zlp520/p/3556822.html